I factored an equation and found two possible roots. But this is not true?

So is it possible for the discriminant(b^2-4ac) to be wrong in certain circumstances?


Because I was able to find two possible roots for an equation...but When I used the discriminant it equaled to a negative number so there should be no roots, but I found a root.





equation- 3x^2 - 2x + 1I factored an equation and found two possible roots. But this is not true?
3x^2 - 2x + 1= 0





discriminant = b^2-4ac


= (-2)^2-4*3*1


= -8%26lt;0


Since discriminat of -8 is less than 0, then there is no real roots.I factored an equation and found two possible roots. But this is not true?
';So is it possible for the discriminant(b^2-4ac) to be wrong in certain circumstances?';


no





If the discriminant is negative, then there are no real roots. There will be complex roots (complex numbers include an imaginary element equal to the square root of -1)





If the discriminant is zero, then the two roots are equal (and will be a real number).
b^2-4ac=4-4(3)(1)=-8


This equation has two complex roots. x=(2+/-sqrt(8)i)/6


What real root did you find that solves this equation??
was the equation '; -34x虏 -2x +1'; ? , if so then 2 roots , -1 %26amp; 1/3, and b虏 - 4ac = 4 -4(-3)(1) = 16