True or false -7 <- (sqaure root)38 <-6?

I'll use * instead of the square root sign.





The problem is -7 %26lt;- *38 %26lt;-6





True or false?True or false -7 %26lt;- (sqaure root)38 %26lt;-6?
true





becuase you know that the square root of 38 is between 6 and 7, because there squares are 36 and 42True or false -7 %26lt;- (sqaure root)38 %26lt;-6?
false


-7=-sqrt(49)


-6=-sqrt(36)


-sqrt(47%26lt;-sqrt(38)%26lt;-sqrt(36)





Without the - signs, it would be true.
true
True.
-7 squared is 49 and -6 squared is 36 so it would be a reasonable conclusion that the negative square root of 38 would be greater than -7 but less than -6.





Final answer: True
True. You can know this by squaring all three numbers, keeping the negative symbols:


-49 %26lt; -38 %26lt; -36
True