is the square root of logx the same as log(x^1/2) ?
I know that log(root x) is the same as x log ^1/2, but I am not so sure if the root is over the log.True or False? Root(log x) = log(x^1/2)?
let x = 10
鈭歭og10=1
log鈭?0=.5
not equal
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